C++

Reference

<type_traits>

class template
<type_traits>

std::decay

template <class T> struct decay;
Decay type
Obtains the decay type of T.

The transformed type is aliased as member type decay::type.

The decay type of T is the same type that results from the standard conversions that happen when an lvalue expression is used as an rvalue, with its cv-qualifier stripped:


This resembles the implicit conversions happening when an argument is passed by value to a function.

Notice that this class merely obtains a type using another type as model, but it does not transform values or objects between those types.

Template parameters

T
A type.

Member types

member typedefinition
typeIf T is a reference type, the type referrered to by T.
Otherwise, T.

Example

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// decay example
#include <iostream>
#include <type_traits>

typedef std::decay<int>::type A;           // int
typedef std::decay<int&>::type B;          // int
typedef std::decay<int&&>::type C;         // int
typedef std::decay<const int&>::type D;    // int
typedef std::decay<int[2]>::type E;        // int*
typedef std::decay<int(int)>::type F;      // int(*)(int)

typedef int X[3];

int main() {
  std::cout << std::boolalpha;
  std::cout << "typedefs of int:" << std::endl;
  std::cout << "A: " << std::is_same<int,A>::value << std::endl;
  std::cout << "B: " << std::is_same<int,B>::value << std::endl;
  std::cout << "C: " << std::is_same<int,C>::value << std::endl;
  std::cout << "D: " << std::is_same<int,D>::value << std::endl;
  std::cout << "E: " << std::is_same<int,E>::value << std::endl;
  std::cout << "F: " << std::is_same<int,F>::value << std::endl;

  return 0;
}

Output:
typedefs of int:
A: true
B: true
C: true
D: true
E: false
F: false


See also

underlying_type
Underlying type of enum (class template)
remove_reference
Remove reference (class template)
remove_cv
Remove cv qualification (class template)