Why its showing wrong ?

[Hasa2019]

Hi there,
I am trying to run a code what school going student can do !
But not sure what kind of mistake I am doing.
Take a look the program

#include<stdio.h>
 void main()
 {
 int X=4;
 do
 {
 printf(“%d”,X);
 X=X+1; 
 }whie(X<=10);
    printf(“ ”);
 } 

The error massage is --expected expression before % token.

Correct answer is 4 5 6 7 8 9 10

Note : Its C language.

[salem c]

https://cboard.cprogramming.com/c-programming/182134-why-its-showing-wrong.html

You're using word processing characters for your double quotes.

[deleted account xyzzy]

There's more wrong than just the use of double quotes. Line 9 it should be while, not whie.

Using a bit of white-space for readability would also be helpful.

#include <stdio.h>

// the preferred return type for main
int main( void )
{
   int X = 4;

   do
   {
      printf( "% d", X );

      X = X + 1;
      // can be shorted to:
      // X++;
   } while ( X <= 10 );

   // add a carriage return to the output
   printf( "\n" );

   // tell the operating system everything went well
   // not required
   return 0;
}

 4 5 6 7 8 9 10

[seeplus]

The do loop can be shortened further to:

    do {
        printf("% d", X);
    } while (++X <= 10);

Also note that in main(), a final return is not needed if the return value is 0.

Also, as there's now only one statement in the do body the {} aren't actually needed. You could use:

    do
        printf("% d", X);
    while (++X <= 10);

[Peter87]

Just because you can doesn't mean you should.
Short code != better code

[Ganado]

do-while without braces is cursed.

[seeplus]

Just because you can doesn't mean you should.

:)

do-while without braces is cursed.

Well it has just been Halloween!