how can i convert a string result to LPVOID?

[Cambalinho]

imagine that my string value is a variable adress. can i convert that value to LPVOID?(i mean the value and not the string adress)

[AbstractionAnon]

No. Let's assume an LPVOID is 32 bits. If your string is more than 4 bytes, how are you going to store that in 32 bits?

[Cambalinho]

but imagine the string value it's: 0x28fac4
how can i add it to LPVOID? i understand that i realy need convert it.

[cire]

If you're storing a pointer value as a string, you're probably doing something very questionable.

#include <cstdint>
#include <iomanip>
#include <iostream>
#include <sstream>
#include <string>

int main()
{
    int i = 5;

    std::cout << &i << '\n';

    void* ptr = &i;
    intptr_t as_int = reinterpret_cast<std::intptr_t>(ptr);

    std::ostringstream oss;
    oss << std::hex << std::showbase << as_int;
    std::cout << oss.str() << '\n';

    as_int = 0;
    ptr = nullptr;

    as_int = std::stoll(oss.str(), nullptr, 16);

    ptr = reinterpret_cast<void*>(as_int);

    std::cout << ptr << '\n';
}

[AbstractionAnon]

I missed that your string value was a variable address.

Any technique for converting a hex value to an unsigned long (assuming LPVOID and unsigned long are the same size) will work.