Value returning function question

[Joeystacks]

How is the definition of the term "expression" affected by value returning functions, and why?

[Peter87]

This sounds like something taken out of context. What definition are you talking about? If this is your homework your teacher might have given you a definition?

[Joeystacks]

An expression is a sequence of operators and their operands

[JLBorges]

An expression has a type and a value category.
The value category is different for functions returning references and functions returning values.

With int& foo() ; the expression foo() has type int and value category lvalue

With int bar() ; the expression bar() has type int and value category prvalue (pure rvalue)

See: http://en.cppreference.com/w/cpp/language/value_category

[Peter87]

Joeystacks wrote:

An expression is a sequence of operators and their operands

Then the question is probably how this definition has to be changed to also include the use of function calls.

[Cubbi]

Function call is an operator (it's even overloadable as "operator()")