You can't. At least not with any variable type I am familiar with.
the >> operator will only handle what the programmer who designed the type you are using it with programmed the operator to do.
With default types (number based variables and chars) y = x >> n; moves/shifts the bits in the x variable n space to the right and stores the results in y.
With the cin statement, the cin is actually a standardized variable of the ifstream type. It is only programmed to move what is in the "stream" (in this case, what the person types) into an appropriate variable. Only the first >> in your statement does this. The computer doesn't know how to handle the rest. For one thing, string literals (strings that are explicitly written in the code such as "/") are not variables. You cannot move data into them.
Operator overloading. (Edit: Which is not casting) The >> operator is overloaded with an std::istream on the left-hand side, and handles a variety of possible data types on the right hand side, from characters, to string literals, to std::strings, to ints to doubles, etc etc, out of the box.