Why is the second operator function not affecting the variable?

[AL88]

why is the second operator function not affecting itsRadius, thanks

#include<iostream>

class SimpleCircle
{
public:
SimpleCircle(int radius){*itsRadius=radius;}
~SimpleCircle(){}
int GetItsRadius(){return *itsRadius;}
const SimpleCircle& operator++();
const SimpleCircle& operator++(int);
private:
int *itsRadius = new int;
};

const SimpleCircle& SimpleCircle::operator++()
{
++*itsRadius;
return *this;
}

const SimpleCircle& SimpleCircle::operator++(int x)
{
*itsRadius++;
return *this;
}



int main()
{
SimpleCircle ACircle(5);
std::cout<<"Its radius = " <<ACircle.GetItsRadius()<< std::endl;
++ACircle;
std::cout<<"Its radius = " <<ACircle.GetItsRadius()<< std::endl;
ACircle++;
std::cout<<"Its radius = " <<ACircle.GetItsRadius()<< std::endl;
}

[Repeater]

Because you're calling ++ on a pointer, not on the thing being pointed at.

const SimpleCircle& SimpleCircle::operator++(int x)
{
(*itsRadius)++;
return *this;
}

[JLBorges]

Why is the radius accessed through a pointer at all?

#include<iostream>

class SimpleCircle
{
    public:

        explicit SimpleCircle( int radius ) { if( radius > 0 ) itsRadius = radius; }

        int Radius() const { return itsRadius; }

        SimpleCircle& operator++() { ++itsRadius ; return *this ; }

        SimpleCircle operator++(int) { auto old_value = *this ; ++*this ; return old_value ; }

    private: int itsRadius = 1 ;
};

int main()
{
    SimpleCircle ACircle(5);

    std::cout << "Its radius = " << ACircle.Radius() << '\n'; // 5

    std::cout << "Its radius = " << (++ACircle).Radius() << '\n'; // 6

    std::cout << "Its radius = " << (ACircle++).Radius() << '\n'; // 6 (old value before increment)

    std::cout << "Its radius = " << ACircle.Radius() << '\n'; // 7
}