using print or using print
I use gcc (Ubuntu 5.4.1-2ubuntu1~16.04) 5.4.1 20160904
#define print std::cout // works for me
however ...
[code]
using print = std::cout;
results in :
adefs.hpp:13:27: error: ‘cout’ in namespace ‘std’ does not name a type
using print = std::cout;
Thanks in advance
Michel Chassey
#define print std::cout // works for me
however ...
[code]
using print = std::cout;
results in :
adefs.hpp:13:27: error: ‘cout’ in namespace ‘std’ does not name a type
using print = std::cout;
Thanks in advance
Michel Chassey
Why do you even attempt to use "print" rather than using the std::cout directly?
The std::cout is name of a global variable.
The
The std::cout is name of a global variable.
The
using A = B; creates a typename (A) as an alias for an existing typename (B).
An alias declaration creates an alias for a type. eg, using Integer = int ;
std::cout is an object; an alias for an object is a reference.
For example: auto& print = std::cout ; // print is an alias for std::cout
std::cout is an object; an alias for an object is a reference.
For example: auto& print = std::cout ; // print is an alias for std::cout
Last edited on
I just remembered from very recent reading that the word
"using" is a kind of typedef, while #define will "____" a new
macro. Didn't have time to edit my post
?Thanks for the fast headsup
Michel Chassey
ps isn't print a command from BASIC ?
"using" is a kind of typedef, while #define will "____" a new
macro. Didn't have time to edit my post
?Thanks for the fast headsup
Michel Chassey
ps isn't print a command from BASIC ?
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