Not understanding the 'OR" operator

[James1st]

I have this simple little program code and I did not get the results I expected.

#include <stdio.h>
#include <iostream>
using namespace std;

int main()
{
    int height = 5;
    int width = 10;

    if (width == printf("123") ||height == 5)
    {
        cout << endl <<("'If' statement evaluated as true") <<endl;
    }
    if (height == 4 || width == printf("123"))
        cout << ("Something is not understood!");
    return 0;
}

The output of the first "if" statement is what I expected.
The output of the second "if" statement is not what I expected. The first parameter,"height ==4" evaluates to false, but the second parameter, "width == printf("123") evaluates to true, so why doesn't the cout command print out the sentence, "Something is not understood!"

[TarikNeaj]

No it does exactly what you tell it to do. Height is not 4. and Width is equal to 10.

[Ganado]

What are you expecting the return value of printf("123") to be?
Because it's not going to be 10. printf returns the number of characters it prints.

[James1st]

Thank you for the responses.
I understand that the output is correct. It is me that is the problem. I don't understand why the last 'cout' is not done. I am seeing the second parameter "width == printf("123") as being true, because as you pointed out, 'width' does indeed, equal 10. . If it is true, I am expecting the block code to be executed.
I need help straightening out my brain process!

[Peter87]

I am seeing the second parameter "width == printf("123") as being true, because as you pointed out, 'width' does indeed, equal 10.

width is 10 but printf("123") does not return 10. It returns 3. 10 is not equal to 3 so the comparison is false.

[James1st]

Of course! Thanks so much for seeing me through this "blind" spot. I really do appreciate it.