Assigning cout() to a variable

[Coubarrie]

I am attempting to assign a cout statement to a (class member)variable with great difficulty. I would be grateful for any assistance available.

I am using the Dev C++ 4.9.9.2 compiler

  rank.First = cout <<weight << ("  pounds" )<< barSize << ("mm  Diameter Bars.");

[Peter87]

Sorry but what are you trying to do? If you was able to assign it to a variable what would the variable contain or be able to do?

[AbstractionAnon]

What is the type of rank.First?
cout is an object of type iostream.
What is it that you expect to be assigned?

You might try using stringstream:
http://www.cplusplus.com/reference/sstream/stringstream/

#include <sstream>

stringstream ss;
string temp;

ss <<weight << ("  pounds" )<< barSize << ("mm  Diameter Bars.");
temp = ss.str();

[giblit]

cout is an object of type iostream.

ostream

If it was iostream there would be no need for cin since it would be input and output.

[Daleth]

std::cout is of type std::ostream.
http://www.cplusplus.com/reference/iostream/cout/

Also, std::ostream is a move-only type, so any assigning will either use a reference or a pointer to std::cout.

[LB]

giblit wrote:

If it was iostream there would be no need for cin since it would be input and output.

http://ideone.com/t9BGIS if only it worked...

[giblit]

That didn't prove anything. You used cout(ostream) for output and cin(istream) for input with an iostream object.

What I was saying anyways is that you can't do this:

std::cout << "enter age: ";
std::cout >> age;

[LB]

giblit wrote:

That didn't prove anything. You used cout(ostream) for output and cin(istream) for input with an iostream object.

I wasn't trying to prove anything. And no, I used the underlying stream buffers from cout and cin, I did not use cout and cin.

[AbstractionAnon]

giblit wrote:

cout is an object of type iostream.

ostream

That was a typo on my part. I had stringstream on the brain.