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Explicit Specialization of Function Templates Help

jasonrobertz357 (56)
why would I need it if I could just make a non template function? I'm confused.
LB (13399)
Because a non=template function cannot overload a template function.
Peter87 (11234)
If you do that you will not get the expected output if you explicitly choose to call the template function.

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#include <iostream>

template <class T>
bool foo(T value)
{
	return true;
}

bool foo(int value)
{
	return false;
}

int main()
{
	std::cout << foo(5) << std::endl;
	std::cout << foo<>(5) << std::endl;
	std::cout << foo<int>(5) << std::endl;	
}
 
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Most people would expect that these three function calls give the same result.
JLBorges (13770)
> why would I need it if I could just make a non template function? I'm confused.

In general, specializing a function template is a bad idea; prefer providing non-template overloads of the function instead.

This was discussed in this thread: http://www.cplusplus.com/forum/beginner/100227/


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