hello,
I would like to know I always understanding that bytes in binary format start with the symbol "\" (antislash) but when I generate random bytes with python sometimes it give me strange result look above :
# and ( are printable characters. Put simply anything in the ASCII range of 32 to 126 is printable, outside of that range, hex would be used. https://ascii.cl/
# is ASCII 35
( is ASCII 40
Those are in the range 32 to 126 and therefore shown as ordinary characters.
A string enclosed in double quotes such as "dog" is actually a sequence of characters ending with a null character (a byte with the value 0). Thus "dog" requires 4 characters.
char word[4] = { 'd', 'o', 'g', 0 };
You could just make the array one byte larger to allow for that null.
I don't understand why you are talking about (sorry) because the code here don't have any error
but this one : unsigned char test[7] = "\x06\xcf\x10^$\xa8\xab";
have error
however they are same size
-----------------------------------------------------------------------------
char array[] = "abc";
this is most likely because a character got misinterpreted or i should escape it or something
however i'm new to C i don't know too much about problem like that
You might know how long the string is but functions such as strcpy, strlen and printf doesn't. They use the null character to detect that the end of the string has been reached.
Let's look at some of the ways that strings work.
Try this code:
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#include <stdio.h>
int main()
{
char array[] = "abc";
printf("Size of array = %d\n", sizeof(array) );
for (unsignedint i=0; i<sizeof(array); ++i)
printf("%2d %c %02x \n", i+1, array[i], array[i]);
}
This is the output:
Size of array = 4
1 a 61
2 b 62
3 c 63
4 00
By all means look on other internet sites for information. But not everything posted on a forum may be correct. Usually stackoverflow can useful.
This code gave a compiler warning when I tried it:
unsignedchar test[7] = "XV\x95\xec\x1f0\x8b";
[Warning] hex escape sequence out of range [enabled by default]
Putting that into the sample program shown above, this is the output, although the length is 7, there are only six meaningful characters, followed by a null.
Size of array = 7
1 X 58
2 V 56
3 ò 95
4 ý ec
5 f0
6 ï 8b
7 00
Note that the sequence \x1f0 is truncated to just \xf0.
Presumably it should have been x1f followed by an ordinary character '0'. One solution is to put \x1f\x30 where \x30 is the hex representation of the character '0'.
This takes us to here:
unsignedchar array[] = "XV\x95\xec\x1f\x30\x8b";
and corresponding output:
Size of array = 8
1 X 58
2 V 56
3 ò 95
4 ý ec
5 ▼ 1f
6 0 30
7 ï 8b
8 00
Although the resulting executable will have the same behavior these are not all the same: 0x63 is an int literal that will be converted to a char. Some compilers will issue a 'truncation' warning for this. char cat[] = { '\x63', '\x61', '\x74', '\x00' }; will be the same as char cat[] = "\x63\x61\x74"; and not generate a compiler warning. – Bob Reynolds Apr 13 '13 at 0:51
However, it you are using python to generate values to be used in a C program, I can think of two approaches.
1. Using python, write the data to a file. Then later the C program can read from that file.
2. Use python to generate a file containing C source code which can be #included in a C program.
Python code follows:
1. Simply write the data to a (binary) file.
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import os
print ("Testing Urandom\n")
size = 7
data = os.urandom(size)
with open('array.bin', 'wb') as f:
f.write(data)
Although the resulting executable will have the same behavior these are not all the same: 0x63 is an int literal that will be converted to a char. Some compilers will issue a 'truncation' warning for this.
Are you sure? Sounds like a stupid compiler. It shouldn't be that hard for a compiler to figure out that the value is small enough to fit in an unsigned char. If you happen to use such a compiler you can probably turn off this warning anyway. Note that it's not a narrowing conversion so the code is perfectly valid C++ code.