namespace and visibility

[AbstractionAnon]

Does using a namespace affect the visibility of functions?

namespace DDL 
{
class DDLTYP 
{
private:
	void Format (ostream & os) const;

public:
	friend ostream & operator << (ostream & os, const DDLTYP & typ);
};
};

The following code generates a compile error when using a namespace.

C:\DEV\DDLDLL\DDLTYP.cpp(97,6) : error (346) : function "DDL::DDLTYP::Format" is inaccessible

using namespace DDL;
ostream & operator << (ostream & os, const DDL::DDLTYP & typ)
{	typ.Format (os);
	return os;
}

Since operator << is declared as a friend, shouldn't it be able to see Format()? It does indeed see Format() if namespace is not used. Yet when declaring DDLTYP within namespace DDL, Format() becomes inaccessible. If I move Format() to public, it compiles. Why should the use of a namespace make a difference to the visibility of Format() assuming references are properly qualified with the DDL scope?

[Flurite]

Try defining the operator overload function inside the DDL namespace.