HOW CAN I CREATE A RAGGED DYNAMIC ARRAY

[ayanda83]

Hi everyone, I have a school project to create a dynamic ragged array. below is my incomplete code.

#include <iostream>
using namespace std;

typedef *int IntPtr;

int main()
{
   IntPtr *p
   p[1] = new int[6]
   p[2] = new int[7]
   p[3] = new int[8]
   p[4] = new int[3] 
    .
    .
    .

my problem here is that, since the inner arrays are not even, it seems like i need a for-loop for every element of p but i do not believe that that is an ideal solution to my problem because, what if p had 100 elements? does that mean i need 100 for-loops? I don't think so. If anyone has a better idea to solve this problem i would really appreciate it. thanking you in advance

[TheDestroyer]

You can create an array, in which you store the size of each inner array, and then use its elements as the upper-limit for your loop.

I would like to point out that arrays in C and C++ start from 0, not from 1 as your code is.

[JLBorges]

#include <vector>

int main()
{
    // http://www.cprogramming.com/tutorial/stl/vector.html
    std::vector< std::vector<int> > ragged(100) ;
    for( std::size_t i = 0 ; i < ragged.size() ; ++i )
        ragged[i] = std::vector<int>( i%10 + 5,  i ) ;
}

[ayanda83]

@TheDestroyer, Your idea is good, but what i don't like about it is that I have to manually specify the size for each inner array, which takes me back to the question of "What if i've got 100 inner arrays".

@JLBorges, what does the following statement do. vector<int>( i%10 + 5, i ) ; and is it possible to make this a dynamic vector?

[JLBorges]

> what does the following statement do. vector<int>( i%10 + 5, i ) ;

Oh! That was just for illustration - it creartes a vector containing i%10 + 5 int values, each one of those ints initialized with i.

> and is it possible to make this a dynamic vector?

A vector<> is dynamically resizeable.
See: http://www.cplusplus.com/reference/stl/vector/