OUTPUT???

[Sibendu Dey]

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
const char arr[]="ABCD";
fun(){
printf("SIze of arr %lu\n",sizeof((unsigned long)sizeof(arr)));
}
main(){
clrscr();
fun();
}

[Peter87]

You have forgot the function return types.
void fun(){

int main(){

[Need4Sleep]

You also need to call fun In main

[shadow123]

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

const char* arr = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const char arr2[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";

void fun(void) {
	printf("Size of arr %lu\n",(unsigned long)sizeof(arr));
	printf("Size of arr2 %lu\n",(unsigned long)sizeof(arr2));
	printf("Length of arr %lu\n",(unsigned long)strlen(arr));
}

int main(void) {
	fun();

	return 0;
}

Just wondering: Should not be the size of arr2 4 bytes, too? Because arr and arr2 are both pointers to a string. On my machine arr2 is length of string incl. null terminator...

[Peter87]

shadow123 wrote:

Should not be the size of arr2 4 bytes, too? Because arr and arr2 are both pointers to a string.

arr2 is an array. Not a pointer.

[Sibendu Dey]

just give me the output along with explanation

[Sibendu Dey]

HELP ME Regarding this,thank you!!!

[cnoeval]

We're not going to do it for you. If you want the output, just fix your code and then run it so you can see it for yourself. You're almost there...