ISO c++ forbids declaration of 'iterator' with no type

[minimike08]

I am trying to create a Map structure, but am having a problem with declaring the iterator for the class. Here is my class declaration:


#ifndef MAP_H
#define MAP_H

#include "Set.h"
#include "Pair.h"

using namespace std;

template <class Key, class Value>
class Map : public Set< Pair<Key, Value> >
{
public:

typedef Pair<Key, Value> value_type;
typedef Set< value_type > parent;
typedef parent::iterator iterator;

Map() : parent() {}
Map(Map<Key, Value> & m) : parent(m) {}

Value & operator [] (Key&);
void erase(Key&);
void erase(iterator& itr) {parent::erase(itr);}

iterator find(Key&) const;

protected:

iterator map_insert(value_type & x)
{
parent::insert(x);
return parent::find(x);
}
};

It is complaining about the line: "typedef parent::iterator iterator;"

I don't see a problem with this since the type is declared by the typedef parent. I would appreciate any insight into this problem. Thanks.

[Peter87]

typedef typename parent::iterator iterator;

[minimike08]

Very well done sir. That was what it was looking for. Thanks a lot.