Context Switch

[willie99]

I need help with this code.
Complete the code so that the output is:

Main1 says Hello

Main2 says Hello

Main1 says Hello

You are not allowed to manipulate the code in function main1 or main2 or main. You cannot use pthread, threadCreate, fork, spawn, processCreate.

#include <iostream>

using namespace std;

typedef void (*Ptr)(int);

int numThr=0;

long r0[10],r1[10],r2[10]; // struct with all registered named
long *stack0,*stack1,*stack2;

void save(long *rLocation) {
    asm(//"pushq %rdi\n"
        "mov %rax, (%rdi)\n"
        "mov %rbx, 8(%rdi)\n"
        "mov %rcx, 16(%rdi)\n"
        "mov %rdx, 24(%rdi)\n"
        "mov %rsi, 32(%rdi)\n"
        "mov %r8, 40(%rdi)\n"
        "mov %rbp, 48(%rdi)\n"); //...
}

void load(long *rLocation) {  // similar to the book
    asm(//"popq %rdi\n"
       
        "mov (%rdi), %rax\n"
        "mov 48(%rdi), %rbp\n"
        "mov 40(%rdi), %r8\n"
        "mov 32(%rdi), %rsi\n"
        "mov 24(%rdi), %rdx\n"
        "mov 16(%rdi), %rcx\n"
        "mov 8(%rdi), %rbx\n"
       
        /*"mov 16(%rdi),%rsp\n"*/);    //....
}

int currentThr;

void setStack(long *s) {
    asm("mov %rdi,%rsp\n");
}

void setStackAndRun(long *s,Ptr ptr) {
    asm("mov %rdi,%rsp\n");
    ptr(currentThr);
}

void getStack(long **s) {
    asm("mov %rsp,(%rdi)");
}
 
void startThr(Ptr ptr) {
    numThr++;
    currentThr=numThr;
    if (numThr==1) {
        stack1=((long *)malloc(sizeof(long)*64000))+64000;
        save(r0);
        getStack(&stack0);
        load(r1);
        setStackAndRun(stack1,ptr);
    }
    else if (numThr==2) {
        stack2=((long *)malloc(sizeof(long)*64000))+64000;
        save(r0);
        getStack(&stack0);
        load(r2);
        setStackAndRun(stack2,ptr);
    }
    //ptr(numThreads);
}

void shareCPU(int thread) {
  if (numThr==1) {
      save(r1); // Save out created thread registers
      load(r0); // Load the main thread registers
      setStack(stack0);
      
      // do "opposite" of what we did on lines 36-39
  }
  // Switch stacks back and swap registers
}

void main1(int whoami) {
    while(true) {
        cout << "Main 1 says Hello" << endl;
        shareCPU(whoami);
    }
}

void main2(int whoami) {
    while(true) {
        cout << "Main 2 says Hello" << endl;
        shareCPU(whoami);
    }
}

int main() {
    startThr(main1);
    startThr(main2);
    while(true) {
        shareCPU(0);
    };
    return 0;
}

[salem c]

You need to format your post before more people will even look at it.
https://www.cplusplus.com/articles/jEywvCM9/

[SirEnder125]

You need to format your post before more people will even look at it.

Don't reply unless it is helpful, I'm sure that is more of a problem than the format of
a post.

Complete the code so that the output is:

Main1 says Hello

Main2 says Hello

Main1 says Hello

is that all you want it to do? Sorry if this is a dumb question.

[dutch]

Alexander123 wrote:

Sorry if this is a dumb question.

Don't reply if you're a fucking retard.

[againtry]

https://www.chegg.com/homework-help/questions-and-answers/need-help-finishing-context-switch-program-c---include-using-namespace-std-typedef-void-pt-q56749812

[salem c]

It's all over the place.
https://cboard.cprogramming.com/cplusplus-programming/179601-i-need-help-finishing-context-switch.html

At least they managed (rather were forced to) make a decent job of the presentation.
But they never came back to actually engage in a discussion about issues arising.

[doug4]

I'm sure that is more of a problem than the format of a post.

Most assuredly that is the case. However, if your post is difficult to read, many here won't bother reading it and move on to other posts. The comment was meant to encourage the poster to post in such a way as to make it as easy as possible for a reviewer to read and respond to the code. The easier it is to respond, the more good responses you will get.

Maybe a 13-year old beginner beginner who is combative with everyone who tries to give him advice that he asked for shouldn't be telling experienced forum denizens how to reply. The advice given by @salem c was kind, clear and helpful, whether you realize it or not.

Edit: yeah, I suspect this will be reported, but I believe without merit.

[seeplus]

void shareCPU(int thread) {
	if (numThr == 1) {
		save(r1); // Save out created thread registers
		load(r0); // Load the main thread registers
		setStack(stack0);

		// do "opposite" of what we did on lines 36-39
	}
	// Switch stacks back and swap registers
}

What about when numThr is 2? After startThr(main2); then numThr is 2 and so shareCPU() does nothing??? Shouldn't shareCPU() cycle through the active threads?

[willie99]

Thank you. I got it working.