A lambda with a dangling reference...

[JUANDENT]

Hi,

I have a lambda with a dangling reference (i.e. it captures by reference a number passed by value, i_ below):

template <typename T> auto f1(T i_)
{ // return a lambda with a dangling reference     
  // since i_ will go out of scope at the return of the function     
	auto lambda = [&] {return  i_ + 3; };
		return lambda;
}

I expect the following code to behave badly (accessing a dangling reference), but it does not!

void test()
{
	auto lamda_missingRef = f1(2);

	// i_ is out of scope - it's non existent after the return of f1...
        // this should not behave correctly (should not return 5)
	int a_missingRef = lamda_missingRef();
}

Why does calling lambda_missingRef() work?

Regards,
Juan Dent

[helios]

Since the behavior is undefined, all behaviors, including working, are permissible.

[kbw]

it captures by reference

Really?

[JUANDENT]

it captures by reference because it has [&] in the lambda..