boolean algebra(circuits)

Hi guys,

so I have taken the time to go back and study some computer architecture,I am on the first chapter and doing boolean algebra,using boolean algebra to simplify digital circuits,

anyhow I am giving this function below

F = ABC + ABC' + A'C (' equals compliment so A compliment)

in the book it says it can be simplified to this

AB(C + C')+ A'C

I'm not sure how it can be simplified to that using boolean algebra I have checked the identity table and couldn't find any matching results.

thanks
Last edited on
Adam2016 what book are you using? Anyway, the simplification is done by using the Distributive Law. see link for more detail: https://www.britannica.com/science/distributive-law
hey tib,

I am reading computer system architecture by M. Morris
BTW that isn't really "simplified", (C or C') == 1.
good point. that makes it AB + AC`
which factors the whole thing down to A(B+C`)
right?
Wrong
AB+A'C
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