Help on leap year finder programer

[anoanomous]

I need some on a c++ programming assignment where I am required to create a program that checks for a leap year using a do while loop and also allows the user to exit the program.

This is what I have done so far (not sure if I have done it right so far..)
Please help!

#include <iostream>

using namespace std;
int main()
{
int year;

cout << "Enter a year: ";
cin >> year;

while(year!=0)
{
if (year % 4 == 0)
{
if (year % 100 == 0)
{
if (year % 400 == 0)
cout << year << " is a leap year.";
else
cout << year << " is not a leap year.";
}
else
cout << year << " is a leap year.";
}
else
cout << year << " is not a leap year.";
}
return 0;
}

[JLBorges]

#include <iostream>

int main()
{
    int year ;
    std::cout << "Enter a year: ";

    // if the user entered an year in the gregorian calendar
    if( std::cin >> year && year > 1572 )
    {
        bool leap ;

        if( year%400 == 0 ) leap = true ; // years divisible by 400 are leap years
        else if( year%100 == 0 ) leap = false ; // years divisible by 100 but not divisible by 400 are not leap years
        else leap = year%4 == 0 ; // otherwise, years divisible by 4 are leap years

        if(leap) std::cout << year << " is a leap year\n" ;
        else std::cout << year << " is not a leap year\n" ;

        // alternatively, we can combine the conditions into a single if
        // if ( the year is exactly divisible by 4 and not divisible by 100 )
        //      or ( year is exactly divisible by 400 )
        // then the year is a leap year.
        if( ( ( year%4 == 0 ) && ( year%100 != 0 ) ) || ( year%400 == 0 ) )
            std::cout << year << " is a leap year\n" ;
        else
            std::cout << year << " is not a leap year\n" ;
     }
}