need solution for my script

[FruiYk]

i think my script is pretty okay ( i know its dutch)
you need to guess the number between 0 and 20 and you have 4 try's if you guessed it it wil return 0; but i want to give the option to start over again. i already implemented it in the script if you did not guess the number you will be given the option. but i cant find any solution for it after the sentence
if (a == b) {cout <<"goed geraden"; return 0;}
thanks for your help.


#include <iostream>
#include <cstdlib>
#include <stdio.h>
#include <sstream>
#pragma once
#include <string>
#include <cstdlib>
#include <ctime>
using namespace std;
int main(){
srand(time(NULL));
int a;
string c;
int b = rand()%21;
do{

cout <<"vul getal in tussen 0 en 20: ";
cin >>a;
if (a>=0&&a<=20){
if (a == b) {cout <<"goed geraden"; return 0;}
else if (a >= b) {cout <<"het is lager\n";}
else cout <<"het is hoger\n";}
else cout <<"onder de 20!!\n";
cout <<"nog 3 levens over\n"<<"vul getal in tussen 0 en 20: ";
cin >>a;
if (a>=0&&a<=20){
if (a == b) {cout <<"goed geraden"; return 0;}
else if (a >= b) {cout <<"het is lager\n";}
else cout <<"het is hoger\n";}
else cout <<"onder de 20!!\n";
cout <<"nog 2 levens over\n"<<"vul getal in tussen 0 en 20: ";
cin >>a;
if (a>=0&&a<=20){
if (a == b) {cout <<"goed geraden"; return 0;}
else if (a >= b) {cout <<"het is lager\n";}
else cout <<"het is hoger\n";}
else cout <<"onder de 20!!\n";
cout <<"nog 1 leven over\n"<<"vul getal in tussen 0 en 20: ";
cin >>a;
if (a>=0&&a<=20){
if (a == b) {cout <<"goed geraden"; return 0;}
}
else cout <<"onder de 20!!\n";
cout <<"je bent af ";
cout <<"het getal was: "<<b;
cout <<"\n nog een potje? ja of nee: ";
cin >>c;

}while (c=="ja");


}

[keskiverto]

You have

int main() {
  // code
  // code you want to repeat
}

Move that something to a separate function:

void guessinggame() {
  // code you want to repeat
}

int main() {
  // code
  guessinggame();
}

That makes the main() look simpler and you can focus there on the "start over and do again". The content of guessinggame() is not related to repeating it.