Convert custom String to C-Style string

[gedamial]

Hi.

I have my own GString class, built using a char* called mainString

I have these methods to allow conversion from my GString class to char*

GString::operator const char*() const
{
	return mainString;
}

GString::operator char*() const
{
	return mainString;
}

The problem is, whenever I try to call my static function:

(static) bool GString::StrStr(GString source, GString substr)
{ 
   ... 
}

int main()
{
   bool check = GString::StrStr("hello", "byebye");
}

The compiler claims:


Error C2664 'bool GString::StrStr(GString,GString)': cannot convert argument 1 from 'const char [14]' to 'GString'


I have an explicit constructor to construct a GString starting from a char*

explicit GString(const char* CstyleString = "");

[dhayden]

I have an explicit constructor to construct a GString starting from a char*

Yes, but you are asking the compiler to use an implicit constructor to make GStrings from "hello" and "byebye".

[cire]

explicit means that your constructor will not be considered for an implicit conversion. It must be used explicitly, and since you aren't using your constructor explicitly here, the compiler cannot use it implicitly.

Yes, but you are asking the compiler to use an implicit constructor to make GStrings from "hello" and "byebye".

Usually when one refers to an implicit constructor, one refers to one implicitly generated by the compiler: not one that is not designated explicit.

[JLBorges]

A constructor declared without the function-specifier explicit specifies a conversion from the types of its parameters to the type of its class. Such a constructor is called a converting constructor. - IS