Why is this giving me a value of 1?

[turtlesavage]

std::cout << (1/1) + (1/2) + (1/3) + (1/4) + (1/5) << std::endl ;

[TheIdeasMan]

Integer division :+)

[turtlesavage]

How would I tell it the it's a long double?

[turtlesavage]

Nevermind.

The answer is

((long double)1/(long double)1)

[Peter87]

Dividing two integers will give you an integer in C++. The first term (1/1) results in 1. The rest result in 0.

std::cout << (1/1) + (1/2) + (1/3) + (1/4) + (1/5) << std::endl;
std::cout << ( 1 ) + ( 0 ) + ( 0 ) + ( 0 ) + ( 0 ) << std::endl;

If you want the result to have a fractional part you should make sure that at least one of the operands is of floating point type (e.g. double). You can do this by including a decimal dot.

std::cout << (1.0/1.0) + (1.0/2.0) + (1.0/3.0) + (1.0/4.0) + (1.0/5.0) << std::endl;