What happens first

[a10e29]

Greetings and Salutations! I have this function call:
temp = grid->getHex(seekerX--, seekerY++);
and the six other variations that search a grid of hexes for possible moves however any conditions in which it pushes onto a vector are always itself.
What happens first the call to getHex (with the original values) or the modification of seeker?
Thanks in advance

[Peter87]

Function arguments are always fully evaluated before they are passed to a function. You use the postfix decrement and increment operators so the old values of seekerX and seekerY will be passed to the function.

[a10e29]

Thanks for the speedy reply. Okay if I were to use getHex((seekerX--),(seeker++) ) be the same as using the prefix operator?

[Peter87]

No. The postfix operators returns the value that the variables had before their values was changed. Parentheses don't change that value.