overloaded * operator

[tay1392]

I know that in the stl list iterator, the * operator returns the current element it's on. My question is, how can I actually output the data inside that element?

It won't let me use the . or -> operator... Is this even possible?

template <typename V, typename E>
void Graph<V, E>::InsertEdge(V from, V to, E edge)
{
	std::list<Vertex<V>*>::iterator iter; //linked list of Vertex pointers
	
	for(iter = m_Vertices.begin(); iter != m_Vertices.end(); ++iter)
	{
		cout << (*iter).m_Data << endl; //How do I display the data in iter?
	}
}

[Peter87]

(*iter)->m_Data should work if Vertex<V> has a member named m_Data that match one of the operator<< overloads.

[Daleth]

Peter87 is right, though I wonder if this is just a mix-up since you have a container of pointers. *iter returns a pointer which you did not dereference, explaining why (*iter).m_Data and iter->m_Data do not work. In reality, the call to the member should be (*(*iter)).m_Data or the more readable (*iter)->m_Data.

[tay1392]

Okay thanks I will try your suggestion and post my results