Why are destructors called in reverse?

[keskiverto]

1. Is there order for t1 and t2?

2.

Anmol444 wrote:

A's constructor
T's constructor
T's constructor

Look again at:

A::A() : t2( 42 )
{
  t1 = 7;
}

You say that lines 2-4 (the A's constructor) are executed before either t1 or t2 has been constructed. If so, you could not use t1 on line 3 ...

[LB]

Confusion resolution: use the order the constructors end, not the order the constructors start.

[Anmol444]

Oh yea T's constructor must have been called, before, otherwise it wouldn't work.


@LB

Why?

[LB]

Because A's constructor does start before T's, but T's ends before A's

[Anmol444]

But he said Ts start before. But yea T's ends before A's. But how is this supposed to help me?

Im so clueless...

[LB]

A's ctor starts before T's because as soon as it starts it calls T's ctor.

[Anmol444]

Ooo ok, I thought it was the opposite cause technically it didnt start cause no statements from it were really executed. Alright thanks guys, I got it I shall use the first person's reply and cire's reply as the reason. Thanks!