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- Help: Output not as nice as I thought
Help: Output not as nice as I thought
Apr 24, 2013 at 1:56pm
Hi. I want it to output like a table or at least nicely arranged but for some reason it didn't output as I expected it to be.
How should I fix it and make the output look as nice as image 2.
Output image:
Image 1:http://i.imgur.com/DyGI8jH.jpg
Image 2:http://i.imgur.com/uAP9lij.jpg
How should I fix it and make the output look as nice as image 2.
Output image:
Image 1:http://i.imgur.com/DyGI8jH.jpg
Image 2:http://i.imgur.com/uAP9lij.jpg
//truefinalproject.cpp
#include <iostream>
#include <iomanip>
using namespace std;
double celsius(int);
double fahrenheit(int);
int choice;
int counter = 0;
int main()
{
cout << "Please input your choice based on the following choices available:\n";
cout << "\n1. Celsius to Fahrenheit Converter";
cout << "\n2. Fahrenheit to Celsius Converter\n\n";
do
{
cin >> choice;
switch (choice)
{
case 1:
cout << "Printing 'Celsius to Fahrenheit Converter' table from 1'C-100'C\n";
cout << "_______________________________________________________________\n";
for ( int a = 0; a < 4; ++a)
cout << setw(7) << "Celsius" << setw(10) << "Fahrenheit";
for ( int b = 0; b < 25; ++b )
{
for ( int c = 0; c <= 75; c += 25 )
cout << setw(5) << b + c << "'C" << setw(9) << setprecision(1) << fixed << fahrenheit(b + c) << "'F ";
}
cout << setw(62) << 100 << "'C" << setw(9) << fahrenheit(100) << "'F";
++counter;
break;
case 2:
cout << "Printing 'Fahrenheit to Celsius Converter' table from 32'F-312'F\n";
cout << "________________________________________________________________\n";
for ( int d = 0; d < 4; ++d )
cout << setw(7) << "Fahrenheit" << setw(10) << " Celsius ";
for ( int e = 32; e < 77; ++e)
{
for ( int f = 0; f <= 135; f += 45 )
cout << setw(5) << e + f << "'F" << setw(10) << setprecision(1) << fixed << celsius(e + f) << "'C ";
}
cout << setw(65) << 212 << "'F" << setw(6) << celsius(212) << "'C";
++counter;
break;
default:
cout << "You have inputted an invalue choice.\n";
cout << "Please input another choice.\n";
break;
}
}
while (counter < 1);
}
double fahrenheit (int celsius)
{
return static_cast <float> (celsius * (9.0/5.0) + 32);
}
double celsius (int fahrenheit)
{
return static_cast <float>((fahrenheit - 32) * (5.0/9.0));
}
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Apr 24, 2013 at 3:45pm
2 only looks good because the width of the line is exactly the width of the console window. Print a new line character at the end of each line, and at the end of the program.
cout << '\n';
Apr 24, 2013 at 3:53pm
If this is your code, I think you should have been able to figure it out.
I only changed case 1
I only changed case 1
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Last edited on Apr 24, 2013 at 4:04pm
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