This is starting to piss me off :-(

[Minimacfox]

What is wrong with this code?
Compiling error:

`fullname' has not been declared

struct student{
char fullname[30];
char hobby[30];
int ooplevel;
};
int getinfo(student* students[], int size){
    for(int i=0; i<size; i++){
        cout << "Student (" << (i+1) << ")\n";
        cout << "Enter name: ";
        cin.get((students+i)->fullname,30);    <--  [COMPILE ERROR OCCURENCE]
    }
}

[Catfish3]

Do you know what student* students[] means? Array of student pointers. Is this what you want?

[Minimacfox]

Yeah, I want an array of student strucs than can be accesed through the -> (assignment operator) AKA pointers.

The problem for me right now is, that I have problems with accessing the char variables for some reason?!

[Minimacfox]

Oh wait, seems I fixed it with:
cin.get((*students+i)->fullname,30);

Have no idea why this works tho.

[Catfish3]

Just do this: int getinfo(student* students, int size){.


I made a mistake maybe... I need to see more of the code to tell for sure.

[Minimacfox]

Mehh. My program became I giant clusterfuck.

Tho I found the real reason for the problem.

It's not:
int getinfo(student* students[], int size)

But instead:
int getinfo(student students[], int size)
or:
int getinfo(student* students,int size)

They're both the same cause an array is the same as a pointer and the other way around.

Anyways, atleast I learned something today ;)

[Peter87]

Minimacfox wrote:

They're both the same cause an array is the same as a pointer and the other way around.

An array is not the same as a pointer. It's just that both syntaxes, when used in the function parameter list, declares a pointer.

[zb0S216C]

int getinfo(student students[], int size){ // "students" parameter changed
    for(int i=0; i<size; i++){
        cout << "Student (" << (i+1) << ")\n";
        cout << "Enter name: ";
        cin.get((students+i)->fullname,29); // Reduced 2nd parameter to 29 
                                            // to save space for a null-character
    }
}

Minimacfox wrote:

"They're both the same cause an array is the same as a pointer and the other way around."

void Function int Array[] );   // IS: int Array*
void Function int *Array[] );  // IS: int Array**
void Function int Array[][] ); // IS: int Array**  

_Wazzak

[Peter87]

Framework wrote:

cin.get((students+i)->fullname,29); // Reduced 2nd parameter to 29 
                                    // to save space for a null-character 

This is unecessary because get already takes the null-character in to account.

Framework wrote:

void Function int Array[][] ); // IS: int Array**

Even if you add the missing parenthesis this is not valid.

[Catfish3]

Even if you add the missing parenthesis this is not valid.

Indeed. There's a technical reason why you always need to specify all but one of a multidimensional array's dimensions... the computer needs that information to correctly determine the offset... I think.