C++

Forum

 
For Loop help

Embers (1)
I'm trying to to get the individual strings from ATG to TAA, ATG to TGA and ATG to TAG.

Input File:
XATGXXXXXTAAXYATGXXXXXTGAXZATGXXXXXTAGX

Goal:
ATGXXXXXTAA
ATGXXXXXTGA
ATGXXXXXTAG

EDIT ----
So I got the code to print each individual string, but I'm stuck on outputting each different string to a file (number1.txt, number2.txt etc...)
Can someone help?

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
 
    
  for (int i=0;now.find("ATG",i)<now.size();i++) {
        cout << "Index: " << i << endl;
      
      if (TAA<TGA && TAA<TAG) {
          cout << "Found TAA: " << ATG_TAA << endl; 
         i = TAA;
         TAA = now.find ("TAA", TAA+1);
       }
      else if (TGA<TAA && TGA<TAG) {
          cout << "Found TGA: " << ATG_TGA << endl; 
          i = TGA;
          TGA = now.find ("TGA", TGA+1);

      }
      else if (TAG<TAA && TAG<TGA) {
          cout << "Found TAG: " << ATG_TAG << endl; 
          i = TAG;
          TAG = now.find ("TAG", TAG+1); 

      }
Last edited on
Ispil (788)
You may have to use a while loop here, instead of a for loop... If I recall, you cannot manipulate the index beyond the increment that it undergoes after reach completion of the loop. If you use a while loop:

1
2
3
4
5
6
 
int i;
while(i<=number)
{
          //statements
          i++;
}

you can at least manipulate "i" from within the loop itself, which is what you are trying to do here.
Last edited on
keskiverto (10402)
Of course you can modify the counter within for's body just like in while.
While is more logical though.

C11 has regex.
Last edited on
keskiverto (10402)
The revised version scares me:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
 
  for (int i=0;now.find("ATG",i)<now.size();i++) {
        cout << "Index: " << i << endl;
      
      if (TAA<TGA && TAA<TAG) {
          cout << "Found TAA: " << ATG_TAA << endl; 
         i = TAA;
         TAA = now.find ("TAA", TAA+1);
       }
      else if (TGA<TAA && TGA<TAG) {
          cout << "Found TGA: " << ATG_TGA << endl; 
          i = TGA;
          TGA = now.find ("TGA", TGA+1);

      }
      else if (TAG<TAA && TAG<TGA) {
          cout << "Found TAG: " << ATG_TAG << endl; 
          i = TAG;
          TAG = now.find ("TAG", TAG+1); 

      }

We have no idea what the values of TAA, TAG, TGA, and ATG_T?? are when the line 4 is evaluated for the first time.

If the intention is to read the string and then write each found substring into different, sequentially numbered file, then one could make a function that takes a counter and string, opens file, writes string, and closes file.
Topic archived. No new replies allowed.