Possibility to avoid {} in initializer_list instances.

[Daleth]

Is there any possible way to avoid the curly brackets in the following call?

  void funct(initializer_list<int> args){/*...*/}
  //...
  int main(){
     funct( {1,2,3} );   //<--This line
  }

I tried searching it up but got nowhere fast.



On a random note, I like the new "New Topic" box with the "Write your question here" and the automatic code tags. :3

[Thumper]

AFAIK there isn't. By definition initializer_lists are wrapped in braces.

Ah! Just noticing they put that in there as well. That's going to help a lot :P

[LB]

Why do you want to avoid using the curly braces? The items would then be interpreted as individual parameters, and you could just use a vararg function to handle that situation, but your current code is much cleaner.

[Daleth]

Oh, well thank you anyway. I am worried about my team members using my function without the brackets because they won't expect an initializer_list... Even I'm worried about forgetting that I need the brackets and start using the function blindly.

[JLBorges]

A braced-init-list is required.

Except that we can pass an empty initializer list with
funct( std::initializer_list<int>() ) ;

[Thumper]

Daleth wrote:

I'm worried about forgetting that I need the brackets

Fear not. If you forget the brackets the compiler will tell you very clearly that you have made that mistake, then you can correct it swiftly.