overloaded extration operator without namespace std

[Aerion4]

Just wondering if anyone could point me in the right direction. I have a friend extraction operator that works if i include namespace std; but fails if i do not. can anyone give me a hint?

ostream& operator << (ostream &out, coins &value)

this is also a friend function, so i have this in my class.h file (as a friend)
in my functions.h file (as the prototype) and in my functions.cpp file (the logic).

ive tried making it

std::ostream& operator....
std::ostream& operator std::<< (etc)

but i just cant see where im going wrong. My compiler keeps telling me 'ostream does not name a type'

thank you

[AbstractionAnon]

To avoid using namespace std; your declaration should be:

friend std::ostream& operator << (std::ostream &out, coins &value) ;

[Aerion4]

Hey man, thanks a lot. This is exactly what i needed.