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suggestion

orly24 (25)
Please help!!
how to run the > symbol properly??
here's what I've done..
suggestions please...

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while(rat>81)
   {

   y=rand()%15+10;

	switch(y)
	{
		case 10:
		{
			gotoxy(rat10=rat10++, 1);
			rat++;
			printf("10>"); break;
		}
		case 11:
		{
			gotoxy(rat11=rat11++, 2);
			rat++;
			printf("11>"); break;
		}
		case 12:
		{
			gotoxy(rat12=rat12++, 3);
			rat++;
			printf("12>"); break;
		}
		case 13:
		{
			gotoxy(rat13=rat13++, 4);
			rat++;
			printf("13>"); break;
		}
		case 14:
		{
			gotoxy(rat14=rat14++, 5);
			rat++;
			printf("14>"); break;
		}
		case 15:
		{
			gotoxy(rat15=rat15++, 6);
			rat++;
			printf("15>"); break;
		}

	}
	delay(500);
	--x;
	clrscr();
   }

	delay(1000);
	clrscr();
vlad from moscow (6539)
It is not seen what is the initial value of rat and what is the condition of the loop.
Last edited on
orly24 (25)
here what I've done..

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#include <stdio.h>
#include <conio.h>
#include <dos.h>
#include <stdlib.h>

main()
{
   clrscr();
   int ratnum, cd=5, x=120, y, rat10=0, rat11=0, rat12=0, rat13=0, rat14=0, rat15=0, win;
   do
   {
    gotoxy(30,10);
    printf("Enter rat number from 1 to 15: ");
    scanf("%d", &ratnum);
   }
   while(ratnum<=9||ratnum>=16);
   clrscr();
   gotoxy(25,10);
   printf("The game will start in...");
   delay(2000);
   clrscr();
   do
   {
    gotoxy(40,10);
    printf("%d...", cd--);
    delay(1000);
    clrscr();
   }
   while(cd>0);

   //race

   while(x>200)
   {

   y=rand()%(15-10+1)+10;

	switch(y)
	{
		case 10:
		{
			rat10=rat10++;
			gotoxy(rat10, 1);
			printf("10>");break;
		}
		case 11:
		{
			rat11=rat11++;
			gotoxy(rat11, 2);
			printf("11>");break;
		}
		case 12:
		{
			rat12=rat12++;
			gotoxy(rat12, 3);
			printf("12>");break;
		}
		case 13:
		{
			rat13=rat13++;
			gotoxy(rat13, 4);
			printf("13>");break;
		}
		case 14:
		{
			rat14=rat14++;
			gotoxy(rat14, 5);
			printf("14>");break;
		}
		case 15:
		{
			rat15=rat15++;
			gotoxy(rat15, 6);
			printf("15>");break;
		}

	}
	delay(500);
	--x;
   }

	delay(1000);
	clrscr();



   getch();
   return 0;
}
ne555 (10692)
¿what?

By the way, I think that rat15=rat15++; is undefined
Last edited on
Peter87 (11235)
@ne555
I think it is fine because in all cases, the assignment is sequenced after the value computation of the right and left operands. That would mean rat15=rat15++; is equivalent to rat15;.
ne555 (10692)
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#include <iostream>
int main(){
   int n=42;
   n = n++;
   std::cout << n << '\n';
}
 
g++ warning: operation on ‘n’ may be undefined [-Wsequence-point]
43
clang++
42

Last edited on
Cubbi (4774)
Specifically, "value computation" is not all that rat15++ is doing.
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