invalid-iterator-argument.

[tamimaddari]

Hi, I am trying to create a program that will take 10 numbers and then print the sum of the all two adjacent numbers and then sum of 1st and last,2nd and 2nd last;here is the code

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int main()
{
vector<int> input;

for(int i=0;i!=10;i++)
{
  int x;
  cin>>x;
  input.push_back(x);
}
for(auto it=input.begin();it!=input.end()-1;it++)
{
  int k;
  k=*it+(*(it+1));
  cout<<k<<" "<<endl;
  auto j=input.end()-it;
  cout<<*it+*j<<" "<<endl;

}

}

.. but at the 2nd output the compiler is giving the error invalid type argument of unary '*'. where am I wrong?

[Peter87]

input.end()-it returns the distance of it from the end of the vector which is of type std::iterator_traits<std::vector<int>::iterator>::difference_type (typedef of some integer type).

[tamimaddari]

Thanks, now I have re wriitten the code and it works fine. its a bit long though!

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int main()
{
vector<int> input;

for(int i=0;i!=10;i++)
{
  int x;
  cin>>x;
  input.push_back(x);
}
 auto j=input.end();
for(auto it=input.begin();it!=input.end()-1;it++)
{
  int k;
  k=*it+(*(it+1));
  cout<<k<<" ";

  if(j !=input.begin())
  {
      j--;
  cout<<*it+*j<<" ";
  }


}

}