Calling classes from their own constructors

[EindacorDS]

I'm working on a basic game that involves modifying objects. The concept is you find "mods" which you can combine with other "mods" to make a totally new one. I'm wondering if there's a way to set up the constructor for the mod class, so that there is one default constructor, and one constructor that combines 2 objects to create a 3rd. Would this work?

class mod
{
	public:
		mod::mod();
		mod::mod(mod a, mod b);

......and so on

I'm unable to compile this right now, but I really want to continue working on the code before I can test it tonight. Thanks in advance.

[Peter87]

The code looks fine if you just remove mod:: from line 4 and 5. You might want to pass a and b by reference to avoid unnecessary copying.

[EindacorDS]

Great, thanks. I'll do just that and see how it goes tonight. Appreciate the help.

[Catfish2]

Did you know you can define member functions (including constructors and destructors) in the class body?

#include <iostream>

class Example {
public:

    Example()
    {
        std::cout << "Example()" << std::endl;
    }
};

But if you want to split them up:

// this goes in H file
class Example {
public:

    Example();
};

// this goes in CPP file
#include <iostream>

Example::Example()
{
    std::cout << "Example()" << std::endl;
}