do x*x by repeated addition

[astraeos]

I am attempting to implement square() without using the multiplication operator; that is, do x*x by repeated addition. For some reason, however, the number is only being added once, so I am getting x+x rather than x*x. Can anyone offer any suggestions as to what I am doing wrong? Many thanks.

int number = 0;
int result = 0;

cout<<"What would you like to square? ";
cin>>number;

result = number;

for (int counter = number; counter <= 0; counter--);
{
	result += number;
}

cout<<"\nThe answer is: " <<result;

[Peter87]

The problem is with the loop condition.
counter <= 0

[BlackSheep]

for (int counter = number; counter <= 0; counter--)
should be
for (int counter = number; counter > 0; counter--)
Also set result to 0, not number, or loop one less time.

[scapegote]

for (int counter = number; counter > 0; counter--);

The semicolon at the end of this makes this repeat until counter is no longer > 0, then it executes the lines in brackets once and spits out the answer

[astraeos]

Haha. Thank you! I can't believe I missed that!

[scapegote]

No problem, took me a minute or two as well.

[mordreds]

if you want to square a number use the
#include <cmath>

and use the pow(variable,2)
use this instead of the for loop