Pointers - help

[Shifter12345]

I have some homework to do but these pointers are confusing me a lot. So I have this code under:

int funct(list *l41){
  int total=0;
  list *current = l41 -> next;
  while (current){
        cout << "third: " << current -> third << endl;
        cout << "forth : " << current -> forth << endl;
        cout << "fifth : " << current -> fifth << endl;
        cout << "sixth : " << current -> sixth << endl;
        cout << "sevent : " << current -> sevent << endl;
    cout << "---------------------" << endl;
    current = current -> next;
    total += 41 % 10 + 1;
  };
  return total;
};

Now here is the question:
How much storage space in working memory holds the pointer current (defined within a function funct)?

My personal opinion is that the pointer current is int type, so that means that the answer is 4 bytes. My friend on the other hand thinks that the pointer is type list.
What's the answer now?

[Peter87]

current is a pointer to list. You can use sizeof to find out how big it is in bytes.
http://en.cppreference.com/w/cpp/language/sizeof

[Moschops]

My personal opinion is that the pointer current is int type

I see how you're thinking. It's very similar to an int, but it's not an int. It is, as Peter says, an object of type pointer-to-a-list. It will almost certainly be the same size as an int, but it is not an int.

current is definitely not an object of type list. It points to a list, but it's not the list.