Fill my array (question)

[Hashimatsu]

I want the user to put ten numbers in a row to fill my array with values.
Example:

const int s(10);
int v[s], i, value;

for(i = 0; i < s; i++)
    {
        cout << "Enter ten numbers in a row and seperate them with ','.;

        cin >> v[i];
    } 

I want the user to put in '1, 2, 3,...n' to fill the array with values. As it is now the user have to put in a number and press enter, put in another value and press enter.

Thanks for advice

[Shinigami]

No, they can enter: 1 2 3 4 5 6 7 8 9 10 and it will work

[chipp]

cout << "enter: ";

for (int i = 0; i < 10; ++i) {
     cin >> v[i];
}

CMIIW

[vlad from moscow]

You can use std::string for input

std::string input;
cout << "Enter ten numbers in a row and seperate them with ','.;
cin >> input; 

and then convert values in the string in values of the array.

[gtkano]

#include <iostream>
using namespace std;


int main()
{
	const int s(10);
	int v[s];

	char numbers[109]; //the char array in which you will store the imput of the user
        char buffer [s];   //char array that will act as a buffer to hold each number delimited by ','
	int aux=0;         //I used this var to keep track of position in int array v[] 
	int aux1=0;        //I used this var to keep track of position in char array buffer[]


	/*Init Vector*/
	for(int i=0; i<s; i++) 
		v[i] = 0;
	//<<<<<<<<<<<<<<<<<<<<<<<<<<

	/*Get User input */
	cout<<"Enter ten numbers in a row and seperate them with ','.";
	cin.getline(numbers,255);
	//<<<<<<<<<<<<<<<<<<<<<<<<<<

	/*Process array*/
	for(int i=0;  i<109; i++)
	{
		if(numbers[i]!=',')
		{
			buffer[aux1] = numbers[i];
			aux1++; //increas position of buffer
		}
		else 
		{
			v[aux] = atoi(&buffer[0]);  //transform buffer char array in int value and insert it in v[aux]
			aux++;   // increas position of v

			aux1 =0; //reset position of buffer
			memset(buffer, '\0', sizeof(buffer)); //clear buffer
		}
	}
	//<<<<<<<<<<<<<<<<<<<<<<<<<<

	/*Display v[] content*/
	for(int i=0; i<s; i++)
	{
		cout<<v[i]<<endl;
	}
	//<<<<<<<<<<<<<<<<<<<<<<<<<<

	/*w8 for user to press key to exit*/
	cin.get();
	cin.get();
	return 0;
}

User is forced to end the input with ',' so that the last value will be accepted


Using string and vector

#include <iostream>
#include <string>
#include <vector>

using namespace std;


int main()
{
	vector<int> v;

	string numbers; //the string array in which you will store the imput of the user
    string buffer ; //string that will act as a buffer to hold each number delimited by ','

	/*Get User input */
	cout<<"Enter ten numbers in a row and seperate them with ','.";
	getline(cin,numbers);

	/*Process array*/
	for(int i=0;  i<=numbers.size(); i++)
	{
		if(numbers[i]!=',' &&
			i <= (numbers.size()-1))
		{
			buffer += numbers[i];
		}
		else 
		{
			v.push_back( atoi(&buffer[0]) );  //transform buffer string in int value and insert it in v
			buffer.clear();
		}
	}

	/*Display v[] content*/
	for(int i=0; i<v.size(); i++)
	{
		cout<<v[i]<<endl;
	}

	/*w8 for user to press key to exit*/
	cin.get();
	cin.get();
	return 0;
}