DIV/0

[Stewbond]

Is this enough to check for a divide by zero?

double div(double numerator, double denominator)
{
  if (denominator == 0.) return -1.;
  return numerator / denominator;
}

[kbw]

I've used that in the past and it seems to be good enough.

[Peter87]

It could still result in an infinite value.

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#include <iostream> #include <limits> double div(double numerator, double denominator) { if (denominator == 0.) return -1.; return numerator / denominator; } int main() { double a = 1; double b = std::numeric_limits<double>::denorm_min(); std::cout << div(a, b) << std::endl; return 0; }

inf

[Stewbond]

Thanks.