The result doesn't show...

[PSPMAN90]

Ok, Hi, thanks for reading my code. Ok this Function its suppose to calculate the power by 2 or the square root of a value, depending of the entry code.
As you can see, its part of the definition

// Calcula el cuadrado de un valor.
	float MisFunciones::calculo(float val)
	{

		if(codigo == 0)
		{
		   return  pow(valorReal, 2);
		}

		else 
			if(codigo == 1)
			{
			  return sqrt(valorReal);
			 
			}

        else 
             cout << "-1"; ; 

	}

As in main

 cout << "\n\n\tEntre el codigo de entrada:";
	  cin >> code;
      miFunA.setCodigo(code);

      cout << "\n\n\tEntra el valor a calcular:";
      cin >> valor;
      miFunA.setValorReal(valor);

      cout << "\n\n\t El resultado es:";
      miFunA.calculo(valor);

You input the code, the value to calculate and the object will call the calculo function, displaying: El resultado es: . depending of the entry code and value should be a result but its not showing the result as you see:

[url]http://img231.imageshack.us/img231/7271/doesntshowwhyax6.gif

Why? Thanks by the way !

Anyone?

PSPMAN90


EDIT: Ok, this is Ironic! I myself, when I post this here, I get the point, that I wasn't doing this:

cout << "\n\n\t El resultado es:" << miFunA.calculo(valor) << endl;

Now they show! OMG!
My bad! Thanks by the way!
Pleas don't delete this post in case of me getting crazy and on need of professional assistance.
Thanks!

[firedraco]

That image is way too small...anyway, I think the problem is you are passing it the float "val" but you are using a different value when computing the root/square. You are also not outputting the value at all, you need cout << in front of miFunA.calculo(valor);

[Zhuge]

Your method calculo() is not outputting the data, just returning it.

cout << miFunA.calculo(valor);

However, you will want to return -1; instead of couting it in the function body.

Edit: I don't have any problems with image size...