Question about "include"

[AandR2024]

if I program this:

if (mystr == "good")
{
cout <<" response 1";
}
else if (mystr == "bad")
{
cout <<" response 2";
}

is there a way that I can have something like if (mystr includes == "good"). Is that possible? Something like that? Thanks.

[Peter87]

You can use the find member function to search a string. If the string is not found it will return std::string::npos so something like this should work:
if (mystr.find("good") != std::string::npos)

[vlad from moscow]

Yes, you can use member function find:

if ( mystr.find( "good" ) != std::string::npos )

[kbw]

if (mystr.substr("good") != std::string::npos)
{
    // mystr contains 'good'
}

[vlad from moscow]

@kbw

if (mystr.substr("good") != std::string::npos)
{
    // mystr contains 'good'
} 

substr does not accept an argument of type const char[]

[kbw]

My mistake.

[AandR2024]

How would I do multiple things inside the line? Like:
if (mystr.find("good" || "well") != std::string::npos
Because that doesn't work.

[Moschops]

if ( (mystr.find("good")  != std::string::npos) ||
     (mystr.find("well")  != std::string::npos) )
{
}