expression must be a modifiable lvalue error

i have a project i need to write a tic tac toe game using arrays..
i've managed to write everything but i'm having problem when writing the function win() to determine who has won...
i have a
 
char square[3][3]={' ',' ',' ',' ',' ',' ',' ',' ',' '};

im writing this:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
int win()            
{int pwin=5;


if(square[0][0]=='X' &&square[0][1]=='X' && square[0][2]=='X')               
    pwin= 1;

    else if(square[1][0]=='X' &&square[1][1]=='X' && square[1][2]='X')
    pwin=1;

    else if(square[2][0]=='X' &&square[2][1]=='X' && square[2][2]='X')
    pwin=1;

    else if(square[0][0]=='X' &&square[1][0]=='X' && square[2][0]='X')
    pwin=1;

    else if(square[0][1]=='X' &&square[1][1]=='X' && square[2][1]='X')
    pwin=1;

    else if(square[0][2]=='X' &&square[1][2]=='X' && square[2][2]='X')
    pwin=1;

    else if(square[0][0]=='X' &&square[1][1]=='X' && square[2][2]='X')
    pwin=1;

    else if(square[0][2]=='X' &&square[1][1]=='X' && square[2][0]='X')
    pwin=1;

else if(square[0][0]=='O' &&square[0][1]=='O' && square[0][2]=='O')               
    pwin= 2;

    else if(square[1][0]=='O' &&square[1][1]=='O' && square[1][2]='O')
    pwin=2;

    else if(square[2][0]=='O' &&square[2][1]=='O' && square[2][2]='O')
    pwin=2;

    else if(square[0][0]=='O' &&square[1][0]=='O' && square[2][0]='O')
    pwin=2;

    else if(square[0][1]=='O' &&square[1][1]=='O' && square[2][1]='O')
    pwin=2;

    else if(square[0][2]=='O' &&square[1][2]=='O' && square[2][2]='O')
    pwin=2;

    else if(square[0][0]=='O' &&square[1][1]=='O' && square[2][2]='O')
    pwin=2;

    else if(square[0][2]=='O' &&square[1][1]=='O' && square[2][0]='O')
    pwin=2;

   else if (square[0][0] != ' ' && square[0][1] != ' ' && square[0][2] != ' '           && square[1][0] != ' ' &&square[1][1] != ' '
    && square[1][2] != ' ' && square[2][0] != ' ' && square[2][1] != ' ' && square[2][2] != ' ')
    pwin=0;

else
pwin= -1;

return pwin;

in function main i wrote this
1
2
3
4
5
6
7
8
     i=win();
    if(i==1)
    
	cout<<"player 1 won";
    if(i==2)
        cout<<"computer won";
    if(i==0)
        cout<<"Game draw";

now my problem is that im having an expression must be a modifiable lvalue error in win() function after the first if statement.... how to solve it?
thank you
Last edited on
You are using = (assignment) instead of == (equal to comparison) in a few places.
thank you
As Peter87 pointed out using the assignment operator instead of the comparision operator and due to priorities of operations the statement

1
2
    else if(square[1][0]=='X' &&square[1][1]=='X' && square[1][2]='X')
    pwin=1;


is interpretated by the compiler as

1
2
    else if( ( square[1][0]=='X' &&square[1][1]=='X' && square[1][2] ) = 'X' )
    pwin=1;


that is you are trying to assign 'X' to the expression ( square[1][0]=='X' &&square[1][1]=='X' && square[1][2] )
Topic archived. No new replies allowed.