convering string toupper case ..

[sanalbarq]

Hello All ,

How could we convert 'string' type to its upper case ?
In normal , we know the 'char' could be converted easily . But what is about the string ?!


I am waiting your replies as soon as possible ..


Regards ..

[Peter87]

You can loop through the characters in the string and use std::toupper to convert each of them to upper case.

[Pravesh Koirala]

for each character in string
character = touppercase(character)

print string

[vlad from moscow]

		std::string s( "This is a test" );

		std::transform( s.begin(), s.end(), s.begin(), std::toupper );

		std::cout << "s = \"" << s << "\"\n";

[Peter87]

@vlad, There are two versions of std::tolower. One in <cctype> and another in <locale>. If both happen to be declared your code will fail to compile.

[vlad from moscow]

Are you sure that the code will not be compiled?! Inside the transform a function with one parameter is called. At least MS VC++ 2010 compiles it without problem.
In any case you can write

std::transform( s.begin(), s.end(), s.begin(), 
                       [] ( char c ) { return ( std::toupper( c ) ); } );

[AlexK]

@vlad, for this code

std::transform( s.begin(), s.end(), s.begin(), 
                       [] ( char c ) { return ( std::toupper( c ) ); } );

MS VC++ 2010 Ultimate gives:

error C2039: 'transform' : is not a member of 'std'
error C2039: 'toupper' : is not a member of 'std'
error C3861: 'transform': identifier not found
error C2039: 'toupper' : is not a member of 'std'

-----------------------------------------
EDITED:
Works fine and without any errors, but must be like this:

#include <algorithm>
std::transform( s.begin(), s.end(), s.begin(), 
                       [] ( char c ) { return ( toupper( c ) ); } );