naive

[mj1709]

what is at the end of an integer pointer to an array; as in at the end of character pointer to an array , we have '\0' ;

for e.g.

 int *num_string;char *c_string;
scanf("%s",c_string);
i=0;
while(num_string[i]!=0)
{
scanf("%d",num_string[i]);
i++;
}

after we have run the above section of codes what do we expect to have at the end of the entered elements in the integer pointer to arrray; as we have '\0' at the end of character pointer to array.......
any help would be appreciated...thanks.....

[Peter87]

There is nothing that marks the end of an array. Not even char arrays. The reason you often find '\0' at the end of a char array is that that is the way c strings are stored.

If you want you can write a special value to the end of your array to mark the end but a better way is probably to keep track of the size of the array from when it was created.

[vlad from moscow]

We expect that the program will abort.
There is no allocated memory to store read characters.