pass the array to function!

[Thuraya]

Hi,

here in this program the void function should attach the numbers that entered by user with (e) and number of index..



void generateNew(string NewID[], int size)
{
for(int x=0;x<size;x++)// for loop to represent the new numbers
{
cout << "The New ID of item " << (x+1) <<
" is e" << x << NewID[x] << endl;
}

}

BUT, the screen display letters instead of the stored numbers !!
how to solve it?
, BTW there is no errors it compiles successfully

[Zeillinger]

Are the numbers stored in NewID? Weird you are storing numbers as strings. How do you receive the numbers from the user?

[Khaltazar]

It looks like you are making your array a string. You should make the array int if you want it to display numbers correctly.

Also, a tip: Make your variable names more meaningful, it helps us understand your process easier.

[Thuraya]

but in the question they want the array declared as string .!and the user will inter only numbers

the first part of Q is >>Write a C++ program that generates a new user ID from
an array of 7 strings called IDs.

BTW, I've changed it to int and it works .

But, Is it possible to work with string ?

[Kageong]

String also can be use to store number.
i been trying to do a program like this, but no problem been found

#include <iostream>
using namespace std;
int main()
{
    string NewID[3];
    int size=3;
    for(int x=0;x<size;x++)
    cin>>NewID[x];
 
    for(int x=0;x<size;x++)// for loop to represent the new numbers
    cout << "The New ID of item " << (x+1) <<" is e" << x << NewID[x] << endl;
    system ("pause");
    return 0;
}

12345
23456
34567
The New ID of item 1 is e012345
The New ID of item 2 is e123456
The New ID of item 3 is e234567
Press any key to continue . . .

If u still having the problem, i guess the problem come from the part where u let the user enter and store the ID... try have a look at there..

[Thuraya]

yeah , it works with me either because it's all in one function ,

but when the part which attach the number with (e)... in other function it doesn't work with string
dunno why! :/ it works only with int.



void generateNew(string NewID[], int size)
{
for(int x=0;x<size;x++)// for loop to represent the new numbers
{
cout << "The New ID of item " << (x+1) <<
" is e" << x << NewID[x] << endl;
}

}

[Thuraya]

yeah yeah , the problem was that the input was int and array was string

thats why it gives me letters not numbers ,

I changed it , and it works ,

thanks for all of your kind help :>