???

[TheAlliedCentralAxis]

#include <iostream>

using namespace std;

void initialize(int &firstInt, int &secondInt, char &aChar);
void getHoursRate(double &hours, double &rate);
double payCheck(double hours, double rate);
void printCheck(double hours, double rate);
void funcOne(int &x, int &y);
void nextChar(char &aChar);

int main()
{
	int x, y;
	char z;
	double rate, hours;
	double amount;

	initialize(x, y, z);
	getHoursRate(hours, rate);
	amount = payCheck(hours, rate);
	cout << "Paycheck = " << amount << endl;
	funcOne(x, y);
	cout << "x = " << x << " and y = " << y << endl;
	nextChar(z);
	cout << "z = " << z << endl;

	return 0;
}

void initialize(int &firstInt, int &secondInt, char &aChar)
{
	firstInt = 0;
	secondInt = 0;
	aChar = ' ';
}

void getHoursRate(double &hours, double &rate)
{
	cout << "Please enter hours worked: ";
	cin >> hours;
	cout << "Please enter rate of pay: ";
	cin >> rate;
}

double payCheck(double hours, double rate)
{
	double theReturn;

	if (hours <= 40)
		theReturn = hours * rate;
	else
		theReturn = 1.5 * (hours - 40) * rate + 40 * rate;

	return theReturn;
}

void printCheck(double hours, double rate)
{
	cout << "Hours worked: " << hours << endl;
	cout << "Rate worked: " << rate << endl;
	cout << "Amount due: " << payCheck << endl;
}

void funcOne(int &x, int &y)
{
	int entNmbr;

	cout << "Please enter a number: ";
	cin >> entNmbr;
	x = 2 * x + y - entNmbr;
}

void nextChar(char &aChar)
{
	aChar = static_cast<char>(aChar + 1);
}

One thing... The variable payCheck on line 62 does not cause a compiling error. Why? Thank you!

[Zaita]

because payCheck is the name of one of your functions.

[TheAlliedCentralAxis]

I did not know that would work! So what does this mean exactly? Does this make the variable main assume a value of 0?

[Zaita]

Probably a runtime error, or the address of the function.

[TheAlliedCentralAxis]

This can certainly cause disorder in a program! How can I avoid it? What I mean to ask is when a function is defined, does a variable of the same name also initialize?

[Zaita]

cout << "Amount due: " << payCheck(hours, rate) << endl;

[TheAlliedCentralAxis]

Is there a problem with that line of code? I feel I'm missing something. Don't all user-defined functions need parantheses?

[Zaita]

No variable is declared with the same name.

I am assuming you want to call the paycheck function to display the amount due.

cout << "Amount due: " << payCheck(hours, rate) << endl;

That will call payCheck(); and then display the results.

[helios]

For

#include <iostream>

void function(){
	std::cout <<"!\n";
}

int main(){
	std::cout <<function;
	return 0;
}

I get
8: warning: the address of `void function()', will always evaluate as `true'
Consequently, the cout always prints 1. It doesn't make much sense to me.

EDIT: Damn. I took too long and now it seems out of place.

[TheAlliedCentralAxis]

Truth is, I actually noticed this days after writing this code and now I don't even know how this came about... But why does it work? Can functions be used without parantheses?

[Zaita]

No. But none of the code you've provided us with calls printCheck(); So it's never been run.

[TheAlliedCentralAxis]

I just used printCheck and it works...

So why does it work? Why does payCheck run without error?

[Zaita]

does it give you the right answer?

[TheAlliedCentralAxis]

Yes.

[Zaita]

Then it's likely your compiler. Certainly not standard behaviour, or behaviour I would rely on.

GCC will equate the function pointer to 1 and it'll print:

Hours worked: 10
Rate worked: 40
Amount due: 1

[TheAlliedCentralAxis]

Yes, understood. Thank you...
What's GCC mean btw?

[Zaita]

GCC is the name of the compiler. The most-standards complient, and multi-platform. The most dominant compiler on *Nix.

http://gcc.gnu.org/

[QWERTYman]

helios:
you need to put std::cout << function();
instead of std::cout << function;
"function" is the address.
"function()" runs the program (and if it isn't void, sets the function call to the return val).