Output range with increment of 5

[seaminusminus]

Problem:
Write a program whose input is two integers, and whose output is the first integer and subsequent increments of 5 as long as the value is less than or equal to the second integer.

If input is:
-15 10

The output is:
-15 -10 -5 0 5 10
----
Issue:
Can only output the first integer...

Current Code's Output:
-15

#include <iostream>
using namespace std;

int main() {
int input1;
int input2;

   cin >> input1;
   cin >> input2;
   
   if (input2 < input1){
      cout << "Second integer can't be less than the first.";
   }
   else {
      if (input1 != input2){
         cout << input1; 
      
       input1 = input1 + 5; 
       cout << " ";
      }
      
      if (input1 == input2){
         cout << input1<< endl;
      }
   }
   return 0;
}

[salem c]

You want a loop, if you want something to happen more than once.

[seeplus]

#include <iostream>

int main() {
    int input1 {}, input2 {};

    std::cin >> input1 >> input2;

    if (input2 < input1)
        return (std::cout << "Second integer can't be less than the first.\n"), 1;

    for (; input1 <= input2; input1 += 5)
           std::cout << input1 << ' ';

    std::cout << '\n';
}

[seaminusminus]

Fixed program w/ loop + bool:

#include <iostream>
using namespace std;

int main() {
    int input1;
    int input2;
    bool isInput2 = false;

   cin >> input1;
   cin >> input2;
   
   if (input2 < input1){
     cout << "Second integer can't be less than the first.";
   }

   else {
      while (input1 <= input2){
         if (input1 != input2){
              isInput2 = false;

                   if (isInput2 == false){
                         cout << input1 << " ";
                         input1 = input1 + 5; 
                         cin >> input1;
                    }
      
                    if (isInput2 == true){
                         cout << input1 << endl;
                    }
     }
   }
   return 0;
}