Why is the buffer not empty?

[janac]

When I run the .exe for this console app without the statement
cin.ignore(1000, '\n');
the window closes when I enter the letter.

If I include the statement above, the window stays open, which is what I want. The output is this:

Type a letter:
v
You typed v
Press any key to quit.

I don't understand why the behavior is different. It implies there's something in the buffer that needs to be ignored, that's feeding

cin.get();

What would that be? I thought

cout << "Press any key to quit.\n";

would flush the buffer.

Here's the program:

#include <iostream>

using namespace std;

int main()
{
	char letter = 'x';

	cout << "Type a letter:\n";
	cin >> letter;

	cout << "You typed " << letter << '\n';

	cin.ignore(1000, '\n');
	cout << "Press any key to quit.\n";
	cin.get();

	return 0;
}

[JLBorges]

> It implies there's something in the buffer that needs to be ignored, that's feeding cin.get();

Yes, there would be (at least) a new line left in the input buffer after formatted input with cin >> letter;
that is feeding cin.get();

Formatted input: http://www.cplusplus.com/forum/beginner/281072/#msg1215707

[janac]

Thanks so much.