ACCESS attributes to fill MULTIMAP

[FORK1]

Write your question here.

  struct source{
string AA BB CC;
source(std::string p1="MARK",std::string p2="21 VEGAS", std::string p3="0645454545") :
AA(p1), BB(p2), CC(p3) {}
}

class BASE{
public;
BASE(BASE& w,source& z);
friend class child;
private:
string ZZ;
source N;

class child:public BASE
{
public:
child ();
///MY PROBLEM is how access attributes of source and BASE to use as parameters //to fill my multimap
void ADD(BASE& a){
    multimap <BASE, string> abo;
    typedef pair <BASE,string> duo;
    typedef multimap < BASE,string> ::iterator it;
    //////////////////////////////::
///ALL OF THIS DIDN'T WORK FOR ME
         //  abo.insert({ a.ZZ, a.N });
 //   abo.insert({ a.ZZ, a.N});
  // BASE(a.ZZ,a.N) =  abo[a.ZZ] ;
 //  abo[BASE(a.ZZ,a.N)]=a.ZZ;

}
}

[keskiverto]

Why does it feel like that you had a different account, which you have removed (and its posts with it)?
http://www.cplusplus.com/forum/beginner/276505/

[FORK1]

yes it is you are right i'm that rabbit so please i'm struggling please i need a help i'm struggling four one week

[FORK1]

EXEMLPE:
abo[BASE(a.ZZ,a.N)] = abo(a.ZZ);

/src/children.cpp:32:40: error: no match for call to ‘(std::multimap<BASE, const std::__cxx11::basic_string<char> >) (const string&)’
   32 |     abo[BASE(a.ZZ,a.N )] = abo(a.ZZ);

[keskiverto]

The abo has type std::multimap<BASE,std::string>
What does the interface of multimap provide? See http://www.cplusplus.com/reference/map/multimap/

* There is no operator[]. Therefore, you can't call abo[x]
* There is no operator(). Therefore, you can't use abo as functor. The abo(y) is not possible. The error message says that.
* For adding elements there is insert(). See http://www.cplusplus.com/reference/map/multimap/insert/
Hence: abo.insert(z);
What type must the z have?

iterator multimap::insert (const value_type& val);
In your case the value_type is duo (aka std::pair<BASE,std::string>)

How does one create a duo object? You need a BASE object and string object:

BASE a;
string w;
abo.insert( duo(a,w) );

You should know yourself what string you want. Your Add() function gets only a BASE as argument.

Note:

Internally, the elements in a multimap are always sorted by its key following a specific strict weak ordering criterion indicated by its internal comparison object (of type Compare).

For your multimap the Compare is less<BASE>.

Therefore, this must be possible:

BASE a, b;
if ( a < b ) 

For that you need bool operator< ( const BASE&, const BASE& );

[FORK1]

Is this necessary because my MULTIMAP have two defferents costum parameters?if so what is the implementation of operator operator< and operator== in this case.
THE AIM IS TO HAVE AN ALPHABETICAL ORDER

Thank

[keskiverto]

Is this necessary because my MULTIMAP have two defferents costum parameters?

Which two parameters?

bool operator< ( const BASE& lhs, const BASE& rhs )
{
  // return true, if lhs is before rhs
  // else return false
}

Multimap does not use operator==.

[FORK1]

But excuse me what do you mean by before rhs exmple: strcmp() ??????
because here we cope with string.

[keskiverto]

If lhs is before rsh (the way you want to order them), then lhs<rhs is true and rhs<lhs is false.

You want alphabetical order "by string". Your BASE has four strings.

std::string has operator< see http://www.cplusplus.com/reference/string/string/operators/

[FORK1]

this is my implimentation it stores witch means abo.insert( duo(a ,a.info) ) worked for me
but when i wanna see the contains by using iterator it does not compile

multimap < BASE,source> abo;
    typedef pair < BASE,source> duo;
    typedef multimap < BASE,source> ::iterator it;
    abo.insert( duo(a ,a.info) );/////worked
    cout<<"--------------------"<<abo.size()<<endl;/////1 

       for(it=abo.begin(); it!=abo.end(); ++it){////////////HERE IS MY PROBLEM
        cout << it->first << " => " << it->second << '\n';

COMPILING ERROR:

 error: expected unqualified-id before ‘=’ token for(it=abo.begin(); it!=abo.end(); ++it){

here is my overloalind < code

bool operator< ( const BASE& a ,const BASE& b )
	     {
    if ( a.nom < b.nom )
	return false;
	else return true;
      }

OVERLOADING WORKS I THINK

[keskiverto]

typedef multimap < BASE,source> ::iterator it;
for ( it = abo.begin(); it != abo.end(); ++it )

What is it?

Do you write other loops like:
for ( int = 0; int < 7; ++int )
or:
for ( int x = 0; x < 7; ++x )

[FORK1]

Yes for sure int is type not a variable but i tried to understand what do you mean .
All i know is "it" is an iterator pointer whereby we can navigate through containers of a multimap.

EXCUSE ME///

[FORK1]

Unfortunately it doesn't work here it is the output:

error: no match for ‘operator<<’ (operand types are ‘std::ostream’ {aka ‘std::basic_ostream<char>’} and ‘source’)cout << it->second<<"----" << endl;
      |             ~~~~ ^~ ~~~~~~~~~~
      |             |           |
      |             |          source
      |             std::ostream {aka std::basic_ostream<char>}

the implementation is

for(multimap <BASE,source> ::iterator it=abo.begin(); it!=abo.end(); ++it){////////////HERE IS MY PROBLEM
            cout << it->first<<"----" << endl;
            cout << it->second<<"----" << endl;

The aime of this is to create a Base class containing name as a private string and a struct containing lastname,adresse, phone but BASE class contains "source info " as private attributes so we want to store those atributes in nient we want to use Base as a key wich can reprsent name i don't know if this is
convinient <BASE,source> i dont know may be this is the best <BASE,string>

[keskiverto]

The error message says that problem is in cout << it->second<<"----" << endl;
You would get the same error with:

source data;
std::cout << data; // error: How to do this? 

You have not defined std::ostream& operator<< ( std::ostream&, const source& );

[FORK1]

yes it is done but unfortunately that wasn't the expected .
What is expected is to have as first ->abo only name of subscriber as a key and in the other hand of the map i 'm supposed to have the information of that subscriber and what i have as out put looks like this .

|WILLIS|HOLLYWOOD|0645454545
----
JIM|9AVENUE|9900900898
////while i want a name in the key i know i can manage the things by changing the key as type string and pointing a.nom but the use of BASE as a key is a MUST .

this is the constractor

BASE:BASE ( std::string& name,source& r)
// Algorithme :
//
{


  name =this->nom ;
   info=r.prenom+"|"+r.adresse+"|"+r.noTelephone;


}

[FORK1]

i think the a part of problem is here abo.insert( duo(a ,a.info) ) we can't point a.name in the first parameter because it will be type string and i want BASE to be my key as a name of subscriber.

[keskiverto]

Think of a table with two columns.
The rows sorted by the first column.
The values in the first column are unique; no same value twice.
The second column has no such restrictions.
Some languages call such table "dictionary".

Why do you have the data in map at all? When you can find a BASE, you can already read its 'info'. You don't need to repeat the 'info' in separate column.

[FORK1]

I think of a second a class and a MAP for further functions.but the problem is solved now and thank you so much .Now my problem is when i have a string forme and i want to split it by specific character.
my form looks like this string S=" name|lastname|adresse|phone"
I used getline (ss ,line,'|') so i think we should have four strings.what i want to do is to split it by only two elements and by the first '|' met.so the string will be in two parts rather than four like before string1= name string2 =lastname|adresse|phone.
i'm stucked.

[keskiverto]

If you call getline (ss ,line,'|') once, you do get string1, don't you?
All the rest is string2.

Or, you split the input to multiple strings and then concatenate all but first back to string2.

[FORK1]

no no no how i'm i stupid thank you so much ,it was a pleasure