Float variable

[semsemdiver]

The output of float variable doesn't give the fraction other decimal place

[code]
#include<iostream>
#include<process.h>
using namespace std;

int main()
{
char again;
do
{

int x;
label: cout<<"please enter number"<<endl;
cin>>x;

while (x<=2)
{
cout<<"Please enter number more than 2"<<endl;
cin>>x;
}

float z;


for(int i=x-1;i>=2;i--)

{

z = x % i;

if(z==0)
{
cout<<x<<"/"<<i<<"="<<z<<endl;
cout<<"this number "<<x<<"is not a primary number"<<endl;
cout<<"try another number?"<<" press 'y' for yes"<<endl;
cin>> again;
if(again=='y')
{
goto label;
}
else
{
exit (0);
}
}

z=x/i;
cout<<x <<"/"<<i <<"= "<<z<<endl; //why the output of z not fractional whilest it is declared as float?
}

cout<<"this number "<<x<<" is a primary number"<<endl;

cout<<"try another number?"<<" press 'y' for yes"<<endl;

cin>>again;

}while (again=='y');

return(0);
}
/code]

[Ganado]

It would help us if you posted a full program as an example, so that it would actually compile, so that we can see what you're talking about.

[semsemdiver]

here you are the whole code, it is a program to examine if the number is a primary or not and ask the user if he needs to try again.

thanks for your help

[semsemdiver]

Hello Ganado
I sent the complete code

[Ganado]

If I'm understanding your issue correctly... when you have two ints, and you divide them, in C++ this does integer division, so the result is a whole number.

If you want "3/4" to be 0.75 instead of 0, then you have to convert one of the operands to a float.

e.g. static_cast<float>(numerator) / denominator

[semsemdiver]

Thank you Ganado, I appreciate your help