C++

Forum

 
 
how to ignore the negative number that is used as a break for the for loop

mcclit (10)
how to ignore the negative number that is used as a break for the for loop?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
 
 #include <iostream>
#include <string>
using namespace std;

int main()
{
	int score, total;
	for (int counter = 0; score > -1; counter++)
	{
		cout << "Please enter non-negative score:";
		cin >> score;
		
		if (score < 0) //this takes a negative number and use it as a break to stop the loop
		{
		    total = score + score; 
		    cout << "true total score is: " << total << endl;
			break;
		}
	}
	return 0;
}
salem c (3700)
Like so?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
 
 #include <iostream>
#include <string>
using namespace std;

int main()
{
	int score = 0, total;  // need to initialise
	for (int counter = 0; score > -1; counter++)
	{
		cout << "Please enter non-negative score:";
		cin >> score;
		
		if (score < 0) //this takes a negative number and use it as a break to stop the loop
		    break;

		total = total + score;  // not score + score
	}
	cout << "true total score is: " << total << endl;
	return 0;
}

mcclit (10)
@salmem_c yes, its working as intended now, thank you
mycuser (92)
Unless I'm missing some very obvious, variable total gets initialized to somewhere around 32764 by gcc.
score value is added to total in the loop.
Topic archived. No new replies allowed.