PR Numbers

[cool123dude]

Problem link : https://www.hackerearth.com/challenges/competitive/march-circuits-19/algorithm/pr-numbers-160aa0c9/
Can anyone help to explain problem statement.
problem statement :

You are given two integers L and R. You are required to find  the count of all the PR numbers in the range L to R inclusively. 
PR number are the numbers which satisfy following 2 properties: -
P:- No pair of adjacent digits are coprime i.e. 2 adjacent digits in a PR number will not be coprime to each other.
R:- PR number is divisible by all the single digit prime numbers which occur as a digit in the PR number.
1<=L,R<=1018

According to me between 1 and 100. These are the PR numbers

1 2 3 4 5 6 7 8 9 20 22 24 26 28 30 33 36 39 40 42 44 46 48 50 55 60 62 63 64 66 68 69 70 77 80 82 84 86 88 90 93 96 99
if this is wrong then correct me .

[salem c]

> Can anyone help to explain problem statement.
Not without registering on the site to find out your question.

[cool123dude]

Problem statement is added ..

[dutch]

I'm not sure if 20, 30, ..., 90 would count. That would mean that 2 and 0 are not coprime, etc. And if they are, then why not 1 and 0?

[cool123dude]

Sorry 1 is not PR number.
I think 20,30..90 should be PR number because 0 and 2 aren't coprime as gcd(0, 2) =2 and 20 is divisible by 2 which is present as a digit in 20

[ne555]

¿why not? 1 has only one digit and it's not prime, so no conditions matter.

[cool123dude]

so, my given numbers are right in between 1 and 100 ?